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Specify a monotonic predictor term in brms. The function does not evaluate its arguments – it exists purely to help set up a model.

Usage

mo(x, id = NA)

Arguments

x

An integer variable or an ordered factor to be modeled as monotonic.

id

Optional character string. All monotonic terms with the same id within one formula will be modeled as having the same simplex (shape) parameter vector. If all monotonic terms of the same predictor have the same id, the resulting predictions will be conditionally monotonic for all values of interacting covariates (Bürkner & Charpentier, 2020).

Details

See Bürkner and Charpentier (2020) for the underlying theory. For detailed documentation of the formula syntax used for monotonic terms, see help(brmsformula) as well as vignette("brms_monotonic").

References

Bürkner P. C. & Charpentier E. (2020). Modeling Monotonic Effects of Ordinal Predictors in Regression Models. British Journal of Mathematical and Statistical Psychology. doi:10.1111/bmsp.12195

See also

Examples

# \dontrun{
# generate some data
income_options <- c("below_20", "20_to_40", "40_to_100", "greater_100")
income <- factor(sample(income_options, 100, TRUE),
                 levels = income_options, ordered = TRUE)
mean_ls <- c(30, 60, 70, 75)
ls <- mean_ls[income] + rnorm(100, sd = 7)
dat <- data.frame(income, ls)

# fit a simple monotonic model
fit1 <- brm(ls ~ mo(income), data = dat)
#> Compiling Stan program...
#> Start sampling
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1: 
#> Chain 1: Gradient evaluation took 2.5e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.25 seconds.
#> Chain 1: Adjust your expectations accordingly!
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#> Chain 1:                0.362 seconds (Total)
#> Chain 1: 
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2: 
#> Chain 2: Gradient evaluation took 2e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.2 seconds.
#> Chain 2: Adjust your expectations accordingly!
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#> Chain 2: 
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3: 
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#> Chain 3: 
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4: 
#> Chain 4: Gradient evaluation took 2.1e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.21 seconds.
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#> Chain 4:                0.367 seconds (Total)
#> Chain 4: 
summary(fit1)
#>  Family: gaussian 
#>   Links: mu = identity 
#> Formula: ls ~ mo(income) 
#>    Data: dat (Number of observations: 100) 
#>   Draws: 4 chains, each with iter = 2000; warmup = 1000; thin = 1;
#>          total post-warmup draws = 4000
#> 
#> Regression Coefficients:
#>           Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> Intercept    29.41      1.47    26.50    32.31 1.00     2609     2083
#> moincome     15.09      0.68    13.78    16.40 1.00     2420     2137
#> 
#> Monotonic Simplex Parameters:
#>              Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> moincome1[1]     0.64      0.04     0.57     0.71 1.00     3150     2489
#> moincome1[2]     0.28      0.04     0.20     0.37 1.00     3851     2229
#> moincome1[3]     0.08      0.04     0.01     0.15 1.00     2605     1540
#> 
#> Further Distributional Parameters:
#>       Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> sigma     7.04      0.51     6.12     8.14 1.00     2876     2192
#> 
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
plot(fit1, N = 6)
#> Warning: Argument 'N' is deprecated. Please use argument 'nvariables' instead.

plot(conditional_effects(fit1), points = TRUE)


# model interaction with other variables
dat$x <- sample(c("a", "b", "c"), 100, TRUE)
fit2 <- brm(ls ~ mo(income)*x, data = dat)
#> Compiling Stan program...
#> Start sampling
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1: 
#> Chain 1: Gradient evaluation took 5.6e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.56 seconds.
#> Chain 1: Adjust your expectations accordingly!
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#> Chain 1:                1.549 seconds (Total)
#> Chain 1: 
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2: 
#> Chain 2: Gradient evaluation took 4.9e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.49 seconds.
#> Chain 2: Adjust your expectations accordingly!
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#> Chain 2: 
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3: 
#> Chain 3: Gradient evaluation took 4.9e-05 seconds
#> Chain 3: 1000 transitions using 10 leapfrog steps per transition would take 0.49 seconds.
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#> Chain 3: 
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4: 
#> Chain 4: Gradient evaluation took 4.6e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.46 seconds.
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#> Chain 4:                1.504 seconds (Total)
#> Chain 4: 
summary(fit2)
#>  Family: gaussian 
#>   Links: mu = identity 
#> Formula: ls ~ mo(income) * x 
#>    Data: dat (Number of observations: 100) 
#>   Draws: 4 chains, each with iter = 2000; warmup = 1000; thin = 1;
#>          total post-warmup draws = 4000
#> 
#> Regression Coefficients:
#>             Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> Intercept      29.57      1.95    25.90    33.43 1.00     2421     2337
#> xb              1.47      2.87    -4.40     6.92 1.00     1839     2140
#> xc             -2.26      2.84    -7.79     3.54 1.00     2093     2429
#> moincome       15.61      1.00    13.66    17.65 1.00     1738     2383
#> moincome:xb    -1.21      1.55    -4.26     1.96 1.00     1630     2151
#> moincome:xc    -0.45      1.52    -3.52     2.44 1.00     1981     2518
#> 
#> Monotonic Simplex Parameters:
#>                 Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> moincome1[1]        0.63      0.04     0.55     0.72 1.00     2861     2692
#> moincome1[2]        0.29      0.04     0.20     0.37 1.00     5405     3029
#> moincome1[3]        0.08      0.04     0.01     0.17 1.00     2450     1444
#> moincome:xb1[1]     0.29      0.22     0.01     0.79 1.00     3393     1977
#> moincome:xb1[2]     0.32      0.23     0.01     0.82 1.00     4500     2794
#> moincome:xb1[3]     0.39      0.25     0.02     0.89 1.00     3621     2213
#> moincome:xc1[1]     0.33      0.23     0.02     0.83 1.00     3992     2011
#> moincome:xc1[2]     0.32      0.23     0.01     0.82 1.00     4411     2297
#> moincome:xc1[3]     0.35      0.23     0.01     0.84 1.00     4811     2943
#> 
#> Further Distributional Parameters:
#>       Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> sigma     7.03      0.52     6.11     8.12 1.00     4805     3196
#> 
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
plot(conditional_effects(fit2), points = TRUE)




# ensure conditional monotonicity
fit3 <- brm(ls ~ mo(income, id = "i")*x, data = dat)
#> Compiling Stan program...
#> Start sampling
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1: 
#> Chain 1: Gradient evaluation took 5.5e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.55 seconds.
#> Chain 1: Adjust your expectations accordingly!
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#> Chain 1:                1.731 seconds (Total)
#> Chain 1: 
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2: 
#> Chain 2: Gradient evaluation took 4.7e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.47 seconds.
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#> Chain 2: 
#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3: 
#> Chain 3: Gradient evaluation took 4.9e-05 seconds
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#> 
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4: 
#> Chain 4: Gradient evaluation took 4.7e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.47 seconds.
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#> Chain 4:                1.619 seconds (Total)
#> Chain 4: 
summary(fit3)
#>  Family: gaussian 
#>   Links: mu = identity 
#> Formula: ls ~ mo(income, id = "i") * x 
#>    Data: dat (Number of observations: 100) 
#>   Draws: 4 chains, each with iter = 2000; warmup = 1000; thin = 1;
#>          total post-warmup draws = 4000
#> 
#> Regression Coefficients:
#>                  Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> Intercept           30.12      2.06    26.17    34.29 1.00     2178     2741
#> xb                   0.19      3.42    -6.59     6.93 1.00     1969     2571
#> xc                  -3.11      3.32    -9.74     3.44 1.00     1966     2331
#> moincomeidEQi       15.14      0.98    13.18    17.03 1.00     1719     2195
#> moincomeidEQi:xb    -0.16      1.51    -3.17     2.79 1.00     1830     2389
#> moincomeidEQi:xc     0.11      1.46    -2.73     2.93 1.00     1825     2117
#> 
#> Monotonic Simplex Parameters:
#>                      Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS
#> moincomeidEQi1[1]        0.65      0.04     0.57     0.72 1.00     3483
#> moincomeidEQi1[2]        0.28      0.04     0.20     0.36 1.00     4371
#> moincomeidEQi1[3]        0.07      0.04     0.01     0.15 1.00     2525
#> moincomeidEQi:xb1[1]     0.65      0.04     0.57     0.72 1.00     3483
#> moincomeidEQi:xb1[2]     0.28      0.04     0.20     0.36 1.00     4371
#> moincomeidEQi:xb1[3]     0.07      0.04     0.01     0.15 1.00     2525
#> moincomeidEQi:xc1[1]     0.65      0.04     0.57     0.72 1.00     3483
#> moincomeidEQi:xc1[2]     0.28      0.04     0.20     0.36 1.00     4371
#> moincomeidEQi:xc1[3]     0.07      0.04     0.01     0.15 1.00     2525
#>                      Tail_ESS
#> moincomeidEQi1[1]        2729
#> moincomeidEQi1[2]        2994
#> moincomeidEQi1[3]        1552
#> moincomeidEQi:xb1[1]     2729
#> moincomeidEQi:xb1[2]     2994
#> moincomeidEQi:xb1[3]     1552
#> moincomeidEQi:xc1[1]     2729
#> moincomeidEQi:xc1[2]     2994
#> moincomeidEQi:xc1[3]     1552
#> 
#> Further Distributional Parameters:
#>       Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> sigma     7.07      0.53     6.13     8.16 1.00     3767     3093
#> 
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
plot(conditional_effects(fit3), points = TRUE)



# }