Specify covariates that vary over different levels
of multi-membership grouping factors thus requiring
special treatment. This function is almost solely useful,
when called in combination with mm.
Outside of multi-membership terms it will behave
very much like cbind.
Arguments
- ...
One or more terms containing covariates corresponding to the grouping levels specified in
mm.
Examples
# \dontrun{
# simulate some data
dat <- data.frame(
y = rnorm(100), x1 = rnorm(100), x2 = rnorm(100),
g1 = sample(1:10, 100, TRUE), g2 = sample(1:10, 100, TRUE)
)
# multi-membership model with level specific covariate values
dat$xc <- (dat$x1 + dat$x2) / 2
fit <- brm(y ~ xc + (1 + mmc(x1, x2) | mm(g1, g2)), data = dat)
#> Compiling Stan program...
#> Start sampling
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1:
#> Chain 1: Gradient evaluation took 4.2e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.42 seconds.
#> Chain 1: Adjust your expectations accordingly!
#> Chain 1:
#> Chain 1:
#> Chain 1: Iteration: 1 / 2000 [ 0%] (Warmup)
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#> Chain 1:
#> Chain 1: Elapsed Time: 0.711 seconds (Warm-up)
#> Chain 1: 0.474 seconds (Sampling)
#> Chain 1: 1.185 seconds (Total)
#> Chain 1:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2:
#> Chain 2: Gradient evaluation took 3.6e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.36 seconds.
#> Chain 2: Adjust your expectations accordingly!
#> Chain 2:
#> Chain 2:
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#> Chain 2:
#> Chain 2: Elapsed Time: 0.75 seconds (Warm-up)
#> Chain 2: 0.479 seconds (Sampling)
#> Chain 2: 1.229 seconds (Total)
#> Chain 2:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3:
#> Chain 3: Gradient evaluation took 3.5e-05 seconds
#> Chain 3: 1000 transitions using 10 leapfrog steps per transition would take 0.35 seconds.
#> Chain 3: Adjust your expectations accordingly!
#> Chain 3:
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#> Chain 3:
#> Chain 3: Elapsed Time: 0.762 seconds (Warm-up)
#> Chain 3: 0.876 seconds (Sampling)
#> Chain 3: 1.638 seconds (Total)
#> Chain 3:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4:
#> Chain 4: Gradient evaluation took 3.5e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.35 seconds.
#> Chain 4: Adjust your expectations accordingly!
#> Chain 4:
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#> Chain 4:
#> Chain 4: Elapsed Time: 0.724 seconds (Warm-up)
#> Chain 4: 0.582 seconds (Sampling)
#> Chain 4: 1.306 seconds (Total)
#> Chain 4:
#> Warning: There were 1 divergent transitions after warmup. See
#> https://mc-stan.org/misc/warnings.html#divergent-transitions-after-warmup
#> to find out why this is a problem and how to eliminate them.
#> Warning: Examine the pairs() plot to diagnose sampling problems
summary(fit)
#> Warning: There were 1 divergent transitions after warmup. Increasing adapt_delta above 0.8 may help. See http://mc-stan.org/misc/warnings.html#divergent-transitions-after-warmup
#> Family: gaussian
#> Links: mu = identity
#> Formula: y ~ xc + (1 + mmc(x1, x2) | mm(g1, g2))
#> Data: dat (Number of observations: 100)
#> Draws: 4 chains, each with iter = 2000; warmup = 1000; thin = 1;
#> total post-warmup draws = 4000
#>
#> Multilevel Hyperparameters:
#> ~mmg1g2 (Number of levels: 10)
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS
#> sd(Intercept) 0.19 0.15 0.01 0.55 1.00 1841
#> sd(mmcx1x2) 0.33 0.24 0.02 0.91 1.00 1306
#> cor(Intercept,mmcx1x2) 0.04 0.57 -0.93 0.94 1.00 2003
#> Tail_ESS
#> sd(Intercept) 1779
#> sd(mmcx1x2) 2045
#> cor(Intercept,mmcx1x2) 2465
#>
#> Regression Coefficients:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> Intercept 0.20 0.13 -0.05 0.45 1.00 2919 1995
#> xc 0.00 0.20 -0.38 0.39 1.00 2902 2197
#>
#> Further Distributional Parameters:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> sigma 0.95 0.07 0.82 1.09 1.00 4748 2897
#>
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
# }