Compute Bayes factors from marginal likelihoods.
Arguments
- x1
A
brmsfitobject- x2
Another
brmsfitobject based on the same responses.- log
Report Bayes factors on the log-scale?
- ...
Additional arguments passed to
bridge_sampler.
Details
Computing the marginal likelihood requires samples
of all variables defined in Stan's parameters block
to be saved. Otherwise bayes_factor cannot be computed.
Thus, please set save_all_pars = TRUE in the call to brm,
if you are planning to apply bayes_factor to your models.
The computation of Bayes factors based on bridge sampling requires
a lot more posterior samples than usual. A good conservative
rule of thumb is perhaps 10-fold more samples (read: the default of 4000
samples may not be enough in many cases). If not enough posterior
samples are provided, the bridge sampling algorithm tends to be unstable,
leading to considerably different results each time it is run.
We thus recommend running bayes_factor
multiple times to check the stability of the results.
More details are provided under
bridgesampling::bayes_factor.
Examples
# \dontrun{
# model with the treatment effect
fit1 <- brm(
count ~ zAge + zBase + Trt,
data = epilepsy, family = negbinomial(),
prior = prior(normal(0, 1), class = b),
save_all_pars = TRUE
)
#> Warning: Argument 'save_all_pars' is deprecated. Please use argument 'all' in function 'save_pars()' instead.
#> Compiling Stan program...
#> Start sampling
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1:
#> Chain 1: Gradient evaluation took 2.9e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.29 seconds.
#> Chain 1: Adjust your expectations accordingly!
#> Chain 1:
#> Chain 1:
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#> Chain 1:
#> Chain 1: Elapsed Time: 0.122 seconds (Warm-up)
#> Chain 1: 0.123 seconds (Sampling)
#> Chain 1: 0.245 seconds (Total)
#> Chain 1:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2:
#> Chain 2: Gradient evaluation took 2.4e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.24 seconds.
#> Chain 2: Adjust your expectations accordingly!
#> Chain 2:
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#> Chain 2:
#> Chain 2: Elapsed Time: 0.123 seconds (Warm-up)
#> Chain 2: 0.128 seconds (Sampling)
#> Chain 2: 0.251 seconds (Total)
#> Chain 2:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3:
#> Chain 3: Gradient evaluation took 2.4e-05 seconds
#> Chain 3: 1000 transitions using 10 leapfrog steps per transition would take 0.24 seconds.
#> Chain 3: Adjust your expectations accordingly!
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#> Chain 3:
#> Chain 3: Elapsed Time: 0.13 seconds (Warm-up)
#> Chain 3: 0.138 seconds (Sampling)
#> Chain 3: 0.268 seconds (Total)
#> Chain 3:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4:
#> Chain 4: Gradient evaluation took 2.5e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.25 seconds.
#> Chain 4: Adjust your expectations accordingly!
#> Chain 4:
#> Chain 4:
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#> Chain 4:
#> Chain 4: Elapsed Time: 0.127 seconds (Warm-up)
#> Chain 4: 0.131 seconds (Sampling)
#> Chain 4: 0.258 seconds (Total)
#> Chain 4:
summary(fit1)
#> Family: negbinomial
#> Links: mu = log
#> Formula: count ~ zAge + zBase + Trt
#> Data: epilepsy (Number of observations: 236)
#> Draws: 4 chains, each with iter = 2000; warmup = 1000; thin = 1;
#> total post-warmup draws = 4000
#>
#> Regression Coefficients:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> Intercept 1.89 0.07 1.75 2.04 1.00 5042 2995
#> zAge 0.11 0.05 0.01 0.21 1.00 4561 3100
#> zBase 0.72 0.05 0.62 0.83 1.00 4811 2858
#> Trt1 -0.19 0.10 -0.39 0.01 1.00 4928 3059
#>
#> Further Distributional Parameters:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> shape 2.36 0.33 1.79 3.05 1.00 4896 3094
#>
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
# model without the treatment effect
fit2 <- brm(
count ~ zAge + zBase,
data = epilepsy, family = negbinomial(),
prior = prior(normal(0, 1), class = b),
save_all_pars = TRUE
)
#> Warning: Argument 'save_all_pars' is deprecated. Please use argument 'all' in function 'save_pars()' instead.
#> Compiling Stan program...
#> Start sampling
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1:
#> Chain 1: Gradient evaluation took 2.7e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.27 seconds.
#> Chain 1: Adjust your expectations accordingly!
#> Chain 1:
#> Chain 1:
#> Chain 1: Iteration: 1 / 2000 [ 0%] (Warmup)
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#> Chain 1:
#> Chain 1: Elapsed Time: 0.121 seconds (Warm-up)
#> Chain 1: 0.114 seconds (Sampling)
#> Chain 1: 0.235 seconds (Total)
#> Chain 1:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2:
#> Chain 2: Gradient evaluation took 2.1e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.21 seconds.
#> Chain 2: Adjust your expectations accordingly!
#> Chain 2:
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#> Chain 2:
#> Chain 2: Elapsed Time: 0.116 seconds (Warm-up)
#> Chain 2: 0.125 seconds (Sampling)
#> Chain 2: 0.241 seconds (Total)
#> Chain 2:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3:
#> Chain 3: Gradient evaluation took 2.6e-05 seconds
#> Chain 3: 1000 transitions using 10 leapfrog steps per transition would take 0.26 seconds.
#> Chain 3: Adjust your expectations accordingly!
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#> Chain 3:
#> Chain 3: Elapsed Time: 0.122 seconds (Warm-up)
#> Chain 3: 0.132 seconds (Sampling)
#> Chain 3: 0.254 seconds (Total)
#> Chain 3:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4:
#> Chain 4: Gradient evaluation took 2.5e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.25 seconds.
#> Chain 4: Adjust your expectations accordingly!
#> Chain 4:
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#> Chain 4: Iteration: 1 / 2000 [ 0%] (Warmup)
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#> Chain 4:
#> Chain 4: Elapsed Time: 0.12 seconds (Warm-up)
#> Chain 4: 0.128 seconds (Sampling)
#> Chain 4: 0.248 seconds (Total)
#> Chain 4:
summary(fit2)
#> Family: negbinomial
#> Links: mu = log
#> Formula: count ~ zAge + zBase
#> Data: epilepsy (Number of observations: 236)
#> Draws: 4 chains, each with iter = 2000; warmup = 1000; thin = 1;
#> total post-warmup draws = 4000
#>
#> Regression Coefficients:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> Intercept 1.80 0.05 1.70 1.90 1.00 3938 2894
#> zAge 0.12 0.05 0.02 0.23 1.00 4306 2981
#> zBase 0.72 0.06 0.62 0.83 1.00 4112 2814
#>
#> Further Distributional Parameters:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> shape 2.32 0.31 1.78 2.99 1.00 4277 2793
#>
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
# compute the bayes factor
bayes_factor(fit1, fit2)
#> Iteration: 1
#> Iteration: 2
#> Iteration: 3
#> Iteration: 4
#> Iteration: 5
#> Iteration: 1
#> Iteration: 2
#> Iteration: 3
#> Iteration: 4
#> Estimated Bayes factor in favor of fit1 over fit2: 0.53920
# }