Posterior Model Probabilities from Marginal Likelihoods
Source:R/bridgesampling.R
post_prob.brmsfit.RdCompute posterior model probabilities from marginal likelihoods.
The brmsfit method is just a thin wrapper around
the corresponding method for bridge objects.
Arguments
- x
A
brmsfitobject.- ...
More
brmsfitobjects or further arguments passed to the underlying post-processing functions. In particular, seeprepare_predictionsfor further supported arguments.- prior_prob
Numeric vector with prior model probabilities. If omitted, a uniform prior is used (i.e., all models are equally likely a priori). The default
NULLcorresponds to equal prior model weights.- model_names
If
NULL(the default) will use model names derived from deparsing the call. Otherwise will use the passed values as model names.
Details
Computing the marginal likelihood requires samples
of all variables defined in Stan's parameters block
to be saved. Otherwise post_prob cannot be computed.
Thus, please set save_all_pars = TRUE in the call to brm,
if you are planning to apply post_prob to your models.
The computation of model probabilities based on bridge sampling requires
a lot more posterior samples than usual. A good conservative
rule of thump is perhaps 10-fold more samples (read: the default of 4000
samples may not be enough in many cases). If not enough posterior
samples are provided, the bridge sampling algorithm tends to be
unstable leading to considerably different results each time it is run.
We thus recommend running post_prob
multiple times to check the stability of the results.
More details are provided under
bridgesampling::post_prob.
Examples
# \dontrun{
# model with the treatment effect
fit1 <- brm(
count ~ zAge + zBase + Trt,
data = epilepsy, family = negbinomial(),
prior = prior(normal(0, 1), class = b),
save_all_pars = TRUE
)
#> Warning: Argument 'save_all_pars' is deprecated. Please use argument 'all' in function 'save_pars()' instead.
#> Compiling Stan program...
#> Start sampling
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1:
#> Chain 1: Gradient evaluation took 2.9e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.29 seconds.
#> Chain 1: Adjust your expectations accordingly!
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#> Chain 1: Elapsed Time: 0.124 seconds (Warm-up)
#> Chain 1: 0.136 seconds (Sampling)
#> Chain 1: 0.26 seconds (Total)
#> Chain 1:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2:
#> Chain 2: Gradient evaluation took 2.2e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.22 seconds.
#> Chain 2: Adjust your expectations accordingly!
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#> Chain 2:
#> Chain 2: Elapsed Time: 0.122 seconds (Warm-up)
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#> Chain 2: 0.256 seconds (Total)
#> Chain 2:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3:
#> Chain 3: Gradient evaluation took 2.3e-05 seconds
#> Chain 3: 1000 transitions using 10 leapfrog steps per transition would take 0.23 seconds.
#> Chain 3: Adjust your expectations accordingly!
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#> Chain 3:
#> Chain 3: Elapsed Time: 0.121 seconds (Warm-up)
#> Chain 3: 0.128 seconds (Sampling)
#> Chain 3: 0.249 seconds (Total)
#> Chain 3:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4:
#> Chain 4: Gradient evaluation took 2.4e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.24 seconds.
#> Chain 4: Adjust your expectations accordingly!
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#> Chain 4: Elapsed Time: 0.127 seconds (Warm-up)
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#> Chain 4: 0.27 seconds (Total)
#> Chain 4:
summary(fit1)
#> Family: negbinomial
#> Links: mu = log
#> Formula: count ~ zAge + zBase + Trt
#> Data: epilepsy (Number of observations: 236)
#> Draws: 4 chains, each with iter = 2000; warmup = 1000; thin = 1;
#> total post-warmup draws = 4000
#>
#> Regression Coefficients:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> Intercept 1.89 0.07 1.76 2.04 1.00 4607 3272
#> zAge 0.11 0.05 0.01 0.21 1.00 5072 3299
#> zBase 0.72 0.05 0.61 0.83 1.00 5279 3168
#> Trt1 -0.19 0.10 -0.38 0.01 1.00 4584 2610
#>
#> Further Distributional Parameters:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> shape 2.35 0.32 1.80 3.05 1.00 4446 2819
#>
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
# model without the treatent effect
fit2 <- brm(
count ~ zAge + zBase,
data = epilepsy, family = negbinomial(),
prior = prior(normal(0, 1), class = b),
save_all_pars = TRUE
)
#> Warning: Argument 'save_all_pars' is deprecated. Please use argument 'all' in function 'save_pars()' instead.
#> Compiling Stan program...
#> Start sampling
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1:
#> Chain 1: Gradient evaluation took 2.9e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.29 seconds.
#> Chain 1: Adjust your expectations accordingly!
#> Chain 1:
#> Chain 1:
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#> Chain 1:
#> Chain 1: Elapsed Time: 0.117 seconds (Warm-up)
#> Chain 1: 0.103 seconds (Sampling)
#> Chain 1: 0.22 seconds (Total)
#> Chain 1:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2:
#> Chain 2: Gradient evaluation took 2.4e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.24 seconds.
#> Chain 2: Adjust your expectations accordingly!
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#> Chain 2:
#> Chain 2: Elapsed Time: 0.113 seconds (Warm-up)
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#> Chain 2: 0.215 seconds (Total)
#> Chain 2:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3:
#> Chain 3: Gradient evaluation took 2.4e-05 seconds
#> Chain 3: 1000 transitions using 10 leapfrog steps per transition would take 0.24 seconds.
#> Chain 3: Adjust your expectations accordingly!
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#> Chain 3:
#> Chain 3: Elapsed Time: 0.118 seconds (Warm-up)
#> Chain 3: 0.126 seconds (Sampling)
#> Chain 3: 0.244 seconds (Total)
#> Chain 3:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4:
#> Chain 4: Gradient evaluation took 2.3e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.23 seconds.
#> Chain 4: Adjust your expectations accordingly!
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#> Chain 4: Elapsed Time: 0.112 seconds (Warm-up)
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#> Chain 4: 0.226 seconds (Total)
#> Chain 4:
summary(fit2)
#> Family: negbinomial
#> Links: mu = log
#> Formula: count ~ zAge + zBase
#> Data: epilepsy (Number of observations: 236)
#> Draws: 4 chains, each with iter = 2000; warmup = 1000; thin = 1;
#> total post-warmup draws = 4000
#>
#> Regression Coefficients:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> Intercept 1.80 0.05 1.70 1.90 1.00 4395 3220
#> zAge 0.13 0.05 0.03 0.23 1.00 3937 3216
#> zBase 0.72 0.06 0.61 0.84 1.00 3996 2929
#>
#> Further Distributional Parameters:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> shape 2.32 0.31 1.77 2.99 1.00 4274 3282
#>
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
# compute the posterior model probabilities
post_prob(fit1, fit2)
#> Iteration: 1
#> Iteration: 2
#> Iteration: 3
#> Iteration: 4
#> Iteration: 5
#> Iteration: 1
#> Iteration: 2
#> Iteration: 3
#> Iteration: 4
#> Iteration: 5
#> fit1 fit2
#> 0.350077 0.649923
# specify prior model probabilities
post_prob(fit1, fit2, prior_prob = c(0.8, 0.2))
#> Iteration: 1
#> Iteration: 2
#> Iteration: 3
#> Iteration: 4
#> Iteration: 5
#> Iteration: 1
#> Iteration: 2
#> Iteration: 3
#> Iteration: 4
#> fit1 fit2
#> 0.6848329 0.3151671
# }