(Soft deprecated) Specify predictors with measurement error. The function does not evaluate its arguments – it exists purely to help set up a model.
Details
For detailed documentation see help(brmsformula).
me terms are soft deprecated in favor of the more
general and consistent mi terms.
By default, latent noise-free variables are assumed
to be correlated. To change that, add set_mecor(FALSE)
to your model formula object (see examples).
Examples
# \dontrun{
# sample some data
N <- 100
dat <- data.frame(
y = rnorm(N), x1 = rnorm(N),
x2 = rnorm(N), sdx = abs(rnorm(N, 1))
)
# fit a simple error-in-variables model
fit1 <- brm(y ~ me(x1, sdx) + me(x2, sdx), data = dat,
save_pars = save_pars(latent = TRUE))
#> Compiling Stan program...
#> Start sampling
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1:
#> Chain 1: Gradient evaluation took 3.6e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.36 seconds.
#> Chain 1: Adjust your expectations accordingly!
#> Chain 1:
#> Chain 1:
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#> Chain 1:
#> Chain 1: Elapsed Time: 2.829 seconds (Warm-up)
#> Chain 1: 1.8 seconds (Sampling)
#> Chain 1: 4.629 seconds (Total)
#> Chain 1:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2:
#> Chain 2: Gradient evaluation took 2e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.2 seconds.
#> Chain 2: Adjust your expectations accordingly!
#> Chain 2:
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#> Chain 2:
#> Chain 2: Elapsed Time: 2.882 seconds (Warm-up)
#> Chain 2: 1.693 seconds (Sampling)
#> Chain 2: 4.575 seconds (Total)
#> Chain 2:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3:
#> Chain 3: Gradient evaluation took 2.1e-05 seconds
#> Chain 3: 1000 transitions using 10 leapfrog steps per transition would take 0.21 seconds.
#> Chain 3: Adjust your expectations accordingly!
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#> Chain 3:
#> Chain 3: Elapsed Time: 2.773 seconds (Warm-up)
#> Chain 3: 1.702 seconds (Sampling)
#> Chain 3: 4.475 seconds (Total)
#> Chain 3:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4:
#> Chain 4: Gradient evaluation took 2.1e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.21 seconds.
#> Chain 4: Adjust your expectations accordingly!
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#> Chain 4: Elapsed Time: 3.045 seconds (Warm-up)
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#> Chain 4: 6.07 seconds (Total)
#> Chain 4:
summary(fit1)
#> Family: gaussian
#> Links: mu = identity
#> Formula: y ~ me(x1, sdx) + me(x2, sdx)
#> Data: dat (Number of observations: 100)
#> Draws: 4 chains, each with iter = 2000; warmup = 1000; thin = 1;
#> total post-warmup draws = 4000
#>
#> Regression Coefficients:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> Intercept 0.07 0.10 -0.13 0.27 1.00 2555 2499
#> mex1sdx 0.25 0.17 -0.11 0.58 1.00 1607 2677
#> mex2sdx -0.10 0.16 -0.42 0.23 1.00 1886 2772
#>
#> Further Distributional Parameters:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> sigma 0.91 0.07 0.78 1.06 1.00 2849 2640
#>
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
# turn off modeling of correlations
bform <- bf(y ~ me(x1, sdx) + me(x2, sdx)) + set_mecor(FALSE)
fit2 <- brm(bform, data = dat, save_pars = save_pars(latent = TRUE))
#> Compiling Stan program...
#> Start sampling
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1:
#> Chain 1: Gradient evaluation took 2.7e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.27 seconds.
#> Chain 1: Adjust your expectations accordingly!
#> Chain 1:
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#> Chain 1:
#> Chain 1: Elapsed Time: 2.401 seconds (Warm-up)
#> Chain 1: 1.548 seconds (Sampling)
#> Chain 1: 3.949 seconds (Total)
#> Chain 1:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2:
#> Chain 2: Gradient evaluation took 1.6e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.16 seconds.
#> Chain 2: Adjust your expectations accordingly!
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#> Chain 2:
#> Chain 2: Elapsed Time: 2.428 seconds (Warm-up)
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#> Chain 2: 5.089 seconds (Total)
#> Chain 2:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3:
#> Chain 3: Gradient evaluation took 1.5e-05 seconds
#> Chain 3: 1000 transitions using 10 leapfrog steps per transition would take 0.15 seconds.
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#> Chain 3: 4.575 seconds (Total)
#> Chain 3:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4:
#> Chain 4: Gradient evaluation took 1.5e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.15 seconds.
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#> Chain 4: Elapsed Time: 2.341 seconds (Warm-up)
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summary(fit2)
#> Family: gaussian
#> Links: mu = identity
#> Formula: y ~ me(x1, sdx) + me(x2, sdx)
#> Data: dat (Number of observations: 100)
#> Draws: 4 chains, each with iter = 2000; warmup = 1000; thin = 1;
#> total post-warmup draws = 4000
#>
#> Regression Coefficients:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> Intercept 0.07 0.11 -0.15 0.28 1.00 3429 2631
#> mex1sdx 0.24 0.18 -0.13 0.59 1.00 1827 2220
#> mex2sdx -0.10 0.16 -0.42 0.21 1.00 1999 3127
#>
#> Further Distributional Parameters:
#> Estimate Est.Error l-95% CI u-95% CI Rhat Bulk_ESS Tail_ESS
#> sigma 0.91 0.07 0.78 1.06 1.00 4228 3188
#>
#> Draws were sampled using sampling(NUTS). For each parameter, Bulk_ESS
#> and Tail_ESS are effective sample size measures, and Rhat is the potential
#> scale reduction factor on split chains (at convergence, Rhat = 1).
# }